(47/12)x=6

Solution for (47/12)x=6 equation:

(47/12)x=6

We move all terms to the left:

(47/12)x-(6)=0


Domain of the equation: 12)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+47/12)x-6=0

We multiply parentheses

47x^2-6=0

a = 47; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·47·(-6)
Δ = 1128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1128}=\sqrt{4*282}=\sqrt{4}*\sqrt{282}=2\sqrt{282}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{282}}{2*47}=\frac{0-2\sqrt{282}}{94}
=-\frac{2\sqrt{282}}{94}
=-\frac{\sqrt{282}}{47}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{282}}{2*47}=\frac{0+2\sqrt{282}}{94}
=\frac{2\sqrt{282}}{94}
=\frac{\sqrt{282}}{47}
$