(48/(x-50))*100=50/x*100

Solution for (48/(x-50))*100=50/x*100 equation:

(48/(x-50))*100=50/x*100

We move all terms to the left:

(48/(x-50))*100-(50/x*100)=0


Domain of the equation: (x-50))*100!=0

x∈R



Domain of the equation: x*100)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(48/(x-50))*100-(+50/x*100)=0

We get rid of parentheses

(48/(x-50))*100-50/x*100=0

We calculate fractions


((48*x*100)/((x-50))*100*x*100)+(-5000x)/((x-50))*100*x*100)=0


We calculate terms in parentheses: +((48*x*100)/((x-50))*100*x*100), so:

(48*x*100)/((x-50))*100*x*100

We add all the numbers together, and all the variables

(+48*x*100)/((x-50))*100*x*100

We multiply all the terms by the denominator


(+48*x*100)

We get rid of parentheses

48*x*100

Wy multiply elements

4800x*1

Wy multiply elements

4800x

Back to the equation:

+(4800x)



We calculate terms in parentheses: +(-5000x)/((x-50))*100*x*100), so:

-5000x)/((x-50))*100*x*100

We multiply all the terms by the denominator


-5000x)

Back to the equation:

+(-5000x))


We get rid of parentheses

4800x-5000x)=0