(48/x+4)(x)=0

Solution for (48/x+4)(x)=0 equation:

(48/x+4)(x)=0


Domain of the equation: x+4)x!=0

x∈R


We multiply parentheses

48x^2+4x=0

a = 48; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·48·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*48}=\frac{-8}{96}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*48}=\frac{0}{96}
=0
$