(48/x+4)+(48/x-4)=5

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Solution for (48/x+4)+(48/x-4)=5 equation: 



(48/x+4)+(48/x-4)=5

We move all terms to the left:

(48/x+4)+(48/x-4)-(5)=0



Domain of the equation: x+4)!=0

x∈R





Domain of the equation: x-4)!=0

x∈R



We get rid of parentheses

48/x+48/x+4-4-5=0

We multiply all the terms by the denominator


4*x-4*x-5*x+48+48=0

We add all the numbers together, and all the variables

-5x+96=0

We move all terms containing x to the left, all other terms to the right

-5x=-96

x=-96/-5

x=19+1/5

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