(490-x)X=560

Solution for (490-x)X=560 equation:

(490-x)x=560

We move all terms to the left:

(490-x)x-(560)=0

We add all the numbers together, and all the variables

(-1x+490)x-560=0

We multiply parentheses

-1x^2+490x-560=0

a = -1; b = 490; c = -560;
Δ = b2-4ac
Δ = 4902-4·(-1)·(-560)
Δ = 237860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{237860}=\sqrt{4*59465}=\sqrt{4}*\sqrt{59465}=2\sqrt{59465}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-2\sqrt{59465}}{2*-1}=\frac{-490-2\sqrt{59465}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+2\sqrt{59465}}{2*-1}=\frac{-490+2\sqrt{59465}}{-2}
$