(4a)(2+2)+(5a)(3+1)=

Solution for (4a)(2+2)+(5a)(3+1)= equation:

Simplifying
(4a)(2 + 2) + (5a)(3 + 1) = 0

Remove parenthesis around (4a)
4a(2 + 2) + (5a)(3 + 1) = 0

Combine like terms: 2 + 2 = 4
4a(4) + (5a)(3 + 1) = 0

Reorder the terms for easier multiplication:
4 * 4a + (5a)(3 + 1) = 0

Multiply 4 * 4
16a + (5a)(3 + 1) = 0

Remove parenthesis around (5a)
16a + 5a(3 + 1) = 0

Combine like terms: 3 + 1 = 4
16a + 5a(4) = 0

Reorder the terms for easier multiplication:
16a + 5 * 4a = 0

Multiply 5 * 4
16a + 20a = 0

Combine like terms: 16a + 20a = 36a
36a = 0

Solving
36a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '36'.
a = 0

Simplifying
a = 0