(4a+1)+(a+5)+(2a-a)=

Solution for (4a+1)+(a+5)+(2a-a)= equation:

Simplifying
(4a + 1) + (a + 5) + (2a + -1a) = 0

Reorder the terms:
(1 + 4a) + (a + 5) + (2a + -1a) = 0

Remove parenthesis around (1 + 4a)
1 + 4a + (a + 5) + (2a + -1a) = 0

Reorder the terms:
1 + 4a + (5 + a) + (2a + -1a) = 0

Remove parenthesis around (5 + a)
1 + 4a + 5 + a + (2a + -1a) = 0

Combine like terms: 2a + -1a = 1a
1 + 4a + 5 + a + (1a) = 0
1 + 4a + 5 + a + (1a) = 0

Reorder the terms:
1 + 5 + 4a + a + (1a) = 0

Combine like terms: 1 + 5 = 6
6 + 4a + a + (1a) = 0

Combine like terms: 4a + a = 5a
6 + 5a + (1a) = 0

Combine like terms: 5a + (1a) = 6a
6 + 6a = 0

Solving
6 + 6a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 6a = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 6a = 0 + -6
6a = 0 + -6

Combine like terms: 0 + -6 = -6
6a = -6

Divide each side by '6'.
a = -1

Simplifying
a = -1