(4a+2h+1s+sin)=

Solution for (4a+2h+1s+sin)= equation:

Simplifying
(4a + 2h + 1s + sin) = 0

Reorder the terms:
(4a + 2h + ins + 1s) = 0

Remove parenthesis around (4a + 2h + ins + 1s)
4a + 2h + ins + 1s = 0

Solving
4a + 2h + ins + 1s = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2h' to each side of the equation.
4a + 2h + ins + -2h + 1s = 0 + -2h

Reorder the terms:
4a + 2h + -2h + ins + 1s = 0 + -2h

Combine like terms: 2h + -2h = 0
4a + 0 + ins + 1s = 0 + -2h
4a + ins + 1s = 0 + -2h
Remove the zero:
4a + ins + 1s = -2h

Add '-1ins' to each side of the equation.
4a + ins + -1ins + 1s = -2h + -1ins

Combine like terms: ins + -1ins = 0
4a + 0 + 1s = -2h + -1ins
4a + 1s = -2h + -1ins

Add '-1s' to each side of the equation.
4a + 1s + -1s = -2h + -1ins + -1s

Combine like terms: 1s + -1s = 0
4a + 0 = -2h + -1ins + -1s
4a = -2h + -1ins + -1s

Divide each side by '4'.
a = -0.5h + -0.25ins + -0.25s

Simplifying
a = -0.5h + -0.25ins + -0.25s