(4a+3)/6=(2a-7)/5

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Solution for (4a+3)/6=(2a-7)/5 equation:



(4a+3)/6=(2a-7)/5
We move all terms to the left:
(4a+3)/6-((2a-7)/5)=0
We calculate fractions
4a/()+(-((2a-7)*6)/()=0
We calculate terms in parentheses: +(-((2a-7)*6)/(), so:
-((2a-7)*6)/(
We multiply all the terms by the denominator
-((2a-7)*6)
We calculate terms in parentheses: -((2a-7)*6), so:
(2a-7)*6
We multiply parentheses
12a-42
Back to the equation:
-(12a-42)
We get rid of parentheses
-12a+42
Back to the equation:
+(-12a+42)
We get rid of parentheses
4a/()-12a+42=0
We multiply all the terms by the denominator
4a-12a*()+42*()=0
We add all the numbers together, and all the variables
4a-12a*()=0

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