(4a+3c)-(2a+4c)=

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Solution for (4a+3c)-(2a+4c)= equation:


Simplifying
(4a + 3c) + -1(2a + 4c) = 0

Remove parenthesis around (4a + 3c)
4a + 3c + -1(2a + 4c) = 0
4a + 3c + (2a * -1 + 4c * -1) = 0
4a + 3c + (-2a + -4c) = 0

Reorder the terms:
4a + -2a + 3c + -4c = 0

Combine like terms: 4a + -2a = 2a
2a + 3c + -4c = 0

Combine like terms: 3c + -4c = -1c
2a + -1c = 0

Solving
2a + -1c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'c' to each side of the equation.
2a + -1c + c = 0 + c

Combine like terms: -1c + c = 0
2a + 0 = 0 + c
2a = 0 + c
Remove the zero:
2a = c

Divide each side by '2'.
a = 0.5c

Simplifying
a = 0.5c

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