(4a+5)(4a+5)=0

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Solution for (4a+5)(4a+5)=0 equation:



(4a+5)(4a+5)=0
We multiply parentheses ..
(+16a^2+20a+20a+25)=0
We get rid of parentheses
16a^2+20a+20a+25=0
We add all the numbers together, and all the variables
16a^2+40a+25=0
a = 16; b = 40; c = +25;
Δ = b2-4ac
Δ = 402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-40}{32}=-1+1/4$

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