(4a+50)=(7a-4)

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Solution for (4a+50)=(7a-4) equation:



(4a+50)=(7a-4)
We move all terms to the left:
(4a+50)-((7a-4))=0
We get rid of parentheses
4a-((7a-4))+50=0
We calculate terms in parentheses: -((7a-4)), so:
(7a-4)
We get rid of parentheses
7a-4
Back to the equation:
-(7a-4)
We get rid of parentheses
4a-7a+4+50=0
We add all the numbers together, and all the variables
-3a+54=0
We move all terms containing a to the left, all other terms to the right
-3a=-54
a=-54/-3
a=+18

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