(4a+8)(3a-2)=0

Solution for (4a+8)(3a-2)=0 equation:

(4a+8)(3a-2)=0

We multiply parentheses ..

(+12a^2-8a+24a-16)=0

We get rid of parentheses

12a^2-8a+24a-16=0

We add all the numbers together, and all the variables

12a^2+16a-16=0

a = 12; b = 16; c = -16;
Δ = b2-4ac
Δ = 162-4·12·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32}{2*12}=\frac{-48}{24}
=-2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32}{2*12}=\frac{16}{24}
=2/3
$