(4a-5)/2=(3a-7)/4

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Solution for (4a-5)/2=(3a-7)/4 equation: 



(4a-5)/2=(3a-7)/4

We move all terms to the left:

(4a-5)/2-((3a-7)/4)=0

We calculate fractions


4a/()+(-((3a-7)*2)/()=0



We calculate terms in parentheses: +(-((3a-7)*2)/(), so:

-((3a-7)*2)/(

We multiply all the terms by the denominator


-((3a-7)*2)



We calculate terms in parentheses: -((3a-7)*2), so:

(3a-7)*2

We multiply parentheses

6a-14

Back to the equation:

-(6a-14)



We get rid of parentheses

-6a+14

Back to the equation:

+(-6a+14)



We get rid of parentheses

4a/()-6a+14=0

We multiply all the terms by the denominator


4a-6a*()+14*()=0

We add all the numbers together, and all the variables

4a-6a*()=0

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