(4a-7)/3=(2+a)/2

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Solution for (4a-7)/3=(2+a)/2 equation: 



(4a-7)/3=(2+a)/2

We move all terms to the left:

(4a-7)/3-((2+a)/2)=0

We add all the numbers together, and all the variables

(4a-7)/3-((a+2)/2)=0

We calculate fractions


4a/()+(-((a+2)*3)/()=0



We calculate terms in parentheses: +(-((a+2)*3)/(), so:

-((a+2)*3)/(

We multiply all the terms by the denominator


-((a+2)*3)



We calculate terms in parentheses: -((a+2)*3), so:

(a+2)*3

We multiply parentheses

3a+6

Back to the equation:

-(3a+6)



We get rid of parentheses

-3a-6

Back to the equation:

+(-3a-6)



We get rid of parentheses

4a/()-3a-6=0

We multiply all the terms by the denominator


4a-3a*()-6*()=0

We add all the numbers together, and all the variables

4a-3a*()=0

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