(4a/2a+3)=5

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Solution for (4a/2a+3)=5 equation: 



(4a/2a+3)=5

We move all terms to the left:

(4a/2a+3)-(5)=0



Domain of the equation: 2a+3)!=0

a∈R



We get rid of parentheses

4a/2a+3-5=0

We multiply all the terms by the denominator


4a+3*2a-5*2a=0

Wy multiply elements

4a+6a-10a=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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