(4b+4)/4=(b+3)/2

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Solution for (4b+4)/4=(b+3)/2 equation: 



(4b+4)/4=(b+3)/2

We move all terms to the left:

(4b+4)/4-((b+3)/2)=0

We calculate fractions


4b/()+(-((b+3)*4)/()=0



We calculate terms in parentheses: +(-((b+3)*4)/(), so:

-((b+3)*4)/(

We multiply all the terms by the denominator


-((b+3)*4)



We calculate terms in parentheses: -((b+3)*4), so:

(b+3)*4

We multiply parentheses

4b+12

Back to the equation:

-(4b+12)



We get rid of parentheses

-4b-12

Back to the equation:

+(-4b-12)



We get rid of parentheses

4b/()-4b-12=0

We multiply all the terms by the denominator


4b-4b*()-12*()=0

We add all the numbers together, and all the variables

4b-4b*()=0

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