(4b+5)/(2b+1)=(6b+1)/(3b-1)

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Solution for (4b+5)/(2b+1)=(6b+1)/(3b-1) equation:


D( b )

3*b-1 = 0

2*b+1 = 0

3*b-1 = 0

3*b-1 = 0

3*b-1 = 0 // + 1

3*b = 1 // : 3

b = 1/3

2*b+1 = 0

2*b+1 = 0

2*b+1 = 0 // - 1

2*b = -1 // : 2

b = -1/2

b in (-oo:-1/2) U (-1/2:1/3) U (1/3:+oo)

(4*b+5)/(2*b+1) = (6*b+1)/(3*b-1) // - (6*b+1)/(3*b-1)

(4*b+5)/(2*b+1)-((6*b+1)/(3*b-1)) = 0

(4*b+5)/(2*b+1)+(-1*(6*b+1))/(3*b-1) = 0

((4*b+5)*(3*b-1))/((2*b+1)*(3*b-1))+(-1*(6*b+1)*(2*b+1))/((2*b+1)*(3*b-1)) = 0

(4*b+5)*(3*b-1)-1*(6*b+1)*(2*b+1) = 0

3*b-6 = 0

(3*b-6)/((2*b+1)*(3*b-1)) = 0

(3*b-6)/((2*b+1)*(3*b-1)) = 0 // * (2*b+1)*(3*b-1)

3*b-6 = 0

3*b-6 = 0 // + 6

3*b = 6 // : 3

b = 6/3

b = 2

b = 2

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