(4b-10)=(2b-2)

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Solution for (4b-10)=(2b-2) equation: 



(4b-10)=(2b-2)

We move all terms to the left:

(4b-10)-((2b-2))=0

We get rid of parentheses

4b-((2b-2))-10=0



We calculate terms in parentheses: -((2b-2)), so:

(2b-2)

We get rid of parentheses

2b-2

Back to the equation:

-(2b-2)



We get rid of parentheses

4b-2b+2-10=0

We add all the numbers together, and all the variables

2b-8=0

We move all terms containing b to the left, all other terms to the right

2b=8

b=8/2

b=4

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