(4b-2c)-(2b-3c)=

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Solution for (4b-2c)-(2b-3c)= equation:


Simplifying
(4b + -2c) + -1(2b + -3c) = 0

Remove parenthesis around (4b + -2c)
4b + -2c + -1(2b + -3c) = 0
4b + -2c + (2b * -1 + -3c * -1) = 0
4b + -2c + (-2b + 3c) = 0

Reorder the terms:
4b + -2b + -2c + 3c = 0

Combine like terms: 4b + -2b = 2b
2b + -2c + 3c = 0

Combine like terms: -2c + 3c = 1c
2b + 1c = 0

Solving
2b + 1c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1c' to each side of the equation.
2b + 1c + -1c = 0 + -1c

Combine like terms: 1c + -1c = 0
2b + 0 = 0 + -1c
2b = 0 + -1c
Remove the zero:
2b = -1c

Divide each side by '2'.
b = -0.5c

Simplifying
b = -0.5c

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