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(4b-3)(5b+6)=0
We multiply parentheses ..
(+20b^2+24b-15b-18)=0
We get rid of parentheses
20b^2+24b-15b-18=0
We add all the numbers together, and all the variables
20b^2+9b-18=0
a = 20; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·20·(-18)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*20}=\frac{-48}{40} =-1+1/5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*20}=\frac{30}{40} =3/4 $
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