(4b-5)=(3b+2)=

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Solution for (4b-5)=(3b+2)= equation: 



(4b-5)=(3b+2)=

We move all terms to the left:

(4b-5)-((3b+2))=0

We get rid of parentheses

4b-((3b+2))-5=0



We calculate terms in parentheses: -((3b+2)), so:

(3b+2)

We get rid of parentheses

3b+2

Back to the equation:

-(3b+2)



We get rid of parentheses

4b-3b-2-5=0

We add all the numbers together, and all the variables

b-7=0

We move all terms containing b to the left, all other terms to the right

b=7

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