(4c)12+(3b)7=

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Solution for (4c)12+(3b)7= equation:


Simplifying
(4c) * 12 + (3b) * 7 = 0

Remove parenthesis around (4c)
4c * 12 + (3b) * 7 = 0

Reorder the terms for easier multiplication:
4 * 12c + (3b) * 7 = 0

Multiply 4 * 12
48c + (3b) * 7 = 0

Remove parenthesis around (3b)
48c + 3b * 7 = 0

Reorder the terms for easier multiplication:
48c + 3 * 7b = 0

Multiply 3 * 7
48c + 21b = 0

Reorder the terms:
21b + 48c = 0

Solving
21b + 48c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-48c' to each side of the equation.
21b + 48c + -48c = 0 + -48c

Combine like terms: 48c + -48c = 0
21b + 0 = 0 + -48c
21b = 0 + -48c
Remove the zero:
21b = -48c

Divide each side by '21'.
b = -2.285714286c

Simplifying
b = -2.285714286c

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