(4c+2)(c+4)=

Solution for (4c+2)(c+4)= equation:

Simplifying
(4c + 2)(c + 4) = 0

Reorder the terms:
(2 + 4c)(c + 4) = 0

Reorder the terms:
(2 + 4c)(4 + c) = 0

Multiply (2 + 4c) * (4 + c)
(2(4 + c) + 4c * (4 + c)) = 0
((4 * 2 + c * 2) + 4c * (4 + c)) = 0
((8 + 2c) + 4c * (4 + c)) = 0
(8 + 2c + (4 * 4c + c * 4c)) = 0
(8 + 2c + (16c + 4c2)) = 0

Combine like terms: 2c + 16c = 18c
(8 + 18c + 4c2) = 0

Solving
8 + 18c + 4c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + 9c + 2c2) = 0

Factor a trinomial.
2((4 + c)(1 + 2c)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(4 + c)' equal to zero and attempt to solve:

Simplifying
4 + c = 0

Solving
4 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + c = 0 + -4
c = 0 + -4

Combine like terms: 0 + -4 = -4
c = -4

Simplifying
c = -4
Subproblem 2
Set the factor '(1 + 2c)' equal to zero and attempt to solve:

Simplifying
1 + 2c = 0

Solving
1 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2c = 0 + -1
2c = 0 + -1

Combine like terms: 0 + -1 = -1
2c = -1

Divide each side by '2'.
c = -0.5

Simplifying
c = -0.5
Solution
c = {-4, -0.5}