(4c+3)(4c-3)=

Solution for (4c+3)(4c-3)= equation:

Simplifying
(4c + 3)(4c + -3) = 0

Reorder the terms:
(3 + 4c)(4c + -3) = 0

Reorder the terms:
(3 + 4c)(-3 + 4c) = 0

Multiply (3 + 4c) * (-3 + 4c)
(3(-3 + 4c) + 4c * (-3 + 4c)) = 0
((-3 * 3 + 4c * 3) + 4c * (-3 + 4c)) = 0
((-9 + 12c) + 4c * (-3 + 4c)) = 0
(-9 + 12c + (-3 * 4c + 4c * 4c)) = 0
(-9 + 12c + (-12c + 16c2)) = 0

Combine like terms: 12c + -12c = 0
(-9 + 0 + 16c2) = 0
(-9 + 16c2) = 0

Solving
-9 + 16c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 16c2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 16c2 = 0 + 9
16c2 = 0 + 9

Combine like terms: 0 + 9 = 9
16c2 = 9

Divide each side by '16'.
c2 = 0.5625

Simplifying
c2 = 0.5625

Take the square root of each side:
c = {-0.75, 0.75}