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Simplifying (4c + 9)(c + 1) = 0 Reorder the terms: (9 + 4c)(c + 1) = 0 Reorder the terms: (9 + 4c)(1 + c) = 0 Multiply (9 + 4c) * (1 + c) (9(1 + c) + 4c * (1 + c)) = 0 ((1 * 9 + c * 9) + 4c * (1 + c)) = 0 ((9 + 9c) + 4c * (1 + c)) = 0 (9 + 9c + (1 * 4c + c * 4c)) = 0 (9 + 9c + (4c + 4c2)) = 0 Combine like terms: 9c + 4c = 13c (9 + 13c + 4c2) = 0 Solving 9 + 13c + 4c2 = 0 Solving for variable 'c'. Factor a trinomial. (9 + 4c)(1 + c) = 0Subproblem 1
Set the factor '(9 + 4c)' equal to zero and attempt to solve: Simplifying 9 + 4c = 0 Solving 9 + 4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + 4c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + 4c = 0 + -9 4c = 0 + -9 Combine like terms: 0 + -9 = -9 4c = -9 Divide each side by '4'. c = -2.25 Simplifying c = -2.25Subproblem 2
Set the factor '(1 + c)' equal to zero and attempt to solve: Simplifying 1 + c = 0 Solving 1 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + c = 0 + -1 c = 0 + -1 Combine like terms: 0 + -1 = -1 c = -1 Simplifying c = -1Solution
c = {-2.25, -1}
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