(4c+9)-3(2c-5)=0

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Solution for (4c+9)-3(2c-5)=0 equation: 



(4c+9)-3(2c-5)=0

We multiply parentheses

(4c+9)-6c+15=0

We get rid of parentheses

4c-6c+9+15=0

We add all the numbers together, and all the variables

-2c+24=0

We move all terms containing c to the left, all other terms to the right

-2c=-24

c=-24/-2

c=+12

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