(4c-1)(8+c)=0

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Solution for (4c-1)(8+c)=0 equation:



(4c-1)(8+c)=0
We add all the numbers together, and all the variables
(4c-1)(c+8)=0
We multiply parentheses ..
(+4c^2+32c-1c-8)=0
We get rid of parentheses
4c^2+32c-1c-8=0
We add all the numbers together, and all the variables
4c^2+31c-8=0
a = 4; b = 31; c = -8;
Δ = b2-4ac
Δ = 312-4·4·(-8)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-33}{2*4}=\frac{-64}{8} =-8 $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+33}{2*4}=\frac{2}{8} =1/4 $

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