(4c-12)-3(6-2c)=c+6

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Solution for (4c-12)-3(6-2c)=c+6 equation: 



(4c-12)-3(6-2c)=c+6

We move all terms to the left:

(4c-12)-3(6-2c)-(c+6)=0

We add all the numbers together, and all the variables

(4c-12)-3(-2c+6)-(c+6)=0

We multiply parentheses

(4c-12)+6c-(c+6)-18=0

We get rid of parentheses

4c+6c-c-12-6-18=0

We add all the numbers together, and all the variables

9c-36=0

We move all terms containing c to the left, all other terms to the right

9c=36

c=36/9

c=4

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