(4c-2)(2c-3)=

Solution for (4c-2)(2c-3)= equation:

Simplifying
(4c + -2)(2c + -3) = 0

Reorder the terms:
(-2 + 4c)(2c + -3) = 0

Reorder the terms:
(-2 + 4c)(-3 + 2c) = 0

Multiply (-2 + 4c) * (-3 + 2c)
(-2(-3 + 2c) + 4c * (-3 + 2c)) = 0
((-3 * -2 + 2c * -2) + 4c * (-3 + 2c)) = 0
((6 + -4c) + 4c * (-3 + 2c)) = 0
(6 + -4c + (-3 * 4c + 2c * 4c)) = 0
(6 + -4c + (-12c + 8c2)) = 0

Combine like terms: -4c + -12c = -16c
(6 + -16c + 8c2) = 0

Solving
6 + -16c + 8c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '2'.
2(3 + -8c + 4c2) = 0

Factor a trinomial.
2((1 + -2c)(3 + -2c)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Subproblem 2
Set the factor '(3 + -2c)' equal to zero and attempt to solve:

Simplifying
3 + -2c = 0

Solving
3 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2c = 0 + -3
-2c = 0 + -3

Combine like terms: 0 + -3 = -3
-2c = -3

Divide each side by '-2'.
c = 1.5

Simplifying
c = 1.5
Solution
c = {0.5, 1.5}