(4c-5)(c-3)=

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Solution for (4c-5)(c-3)= equation:


Simplifying
(4c + -5)(c + -3) = 0

Reorder the terms:
(-5 + 4c)(c + -3) = 0

Reorder the terms:
(-5 + 4c)(-3 + c) = 0

Multiply (-5 + 4c) * (-3 + c)
(-5(-3 + c) + 4c * (-3 + c)) = 0
((-3 * -5 + c * -5) + 4c * (-3 + c)) = 0
((15 + -5c) + 4c * (-3 + c)) = 0
(15 + -5c + (-3 * 4c + c * 4c)) = 0
(15 + -5c + (-12c + 4c2)) = 0

Combine like terms: -5c + -12c = -17c
(15 + -17c + 4c2) = 0

Solving
15 + -17c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + -4c)(3 + -1c) = 0

Subproblem 1

Set the factor '(5 + -4c)' equal to zero and attempt to solve: Simplifying 5 + -4c = 0 Solving 5 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4c = 0 + -5 -4c = 0 + -5 Combine like terms: 0 + -5 = -5 -4c = -5 Divide each side by '-4'. c = 1.25 Simplifying c = 1.25

Subproblem 2

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Solution

c = {1.25, 3}

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