(4c-5)=(2c+7)

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Solution for (4c-5)=(2c+7) equation: 



(4c-5)=(2c+7)

We move all terms to the left:

(4c-5)-((2c+7))=0

We get rid of parentheses

4c-((2c+7))-5=0



We calculate terms in parentheses: -((2c+7)), so:

(2c+7)

We get rid of parentheses

2c+7

Back to the equation:

-(2c+7)



We get rid of parentheses

4c-2c-7-5=0

We add all the numbers together, and all the variables

2c-12=0

We move all terms containing c to the left, all other terms to the right

2c=12

c=12/2

c=6

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