(4c-6)=(2c+5)

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Solution for (4c-6)=(2c+5) equation: 



(4c-6)=(2c+5)

We move all terms to the left:

(4c-6)-((2c+5))=0

We get rid of parentheses

4c-((2c+5))-6=0



We calculate terms in parentheses: -((2c+5)), so:

(2c+5)

We get rid of parentheses

2c+5

Back to the equation:

-(2c+5)



We get rid of parentheses

4c-2c-5-6=0

We add all the numbers together, and all the variables

2c-11=0

We move all terms containing c to the left, all other terms to the right

2c=11

c=11/2

c=5+1/2

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