(4f+3)/5=(f+3)/2

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Solution for (4f+3)/5=(f+3)/2 equation: 



(4f+3)/5=(f+3)/2

We move all terms to the left:

(4f+3)/5-((f+3)/2)=0

We calculate fractions


4f/()+(-((f+3)*5)/()=0



We calculate terms in parentheses: +(-((f+3)*5)/(), so:

-((f+3)*5)/(

We multiply all the terms by the denominator


-((f+3)*5)



We calculate terms in parentheses: -((f+3)*5), so:

(f+3)*5

We multiply parentheses

5f+15

Back to the equation:

-(5f+15)



We get rid of parentheses

-5f-15

Back to the equation:

+(-5f-15)



We get rid of parentheses

4f/()-5f-15=0

We multiply all the terms by the denominator


4f-5f*()-15*()=0

We add all the numbers together, and all the variables

4f-5f*()=0

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