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(4g+7)(g+8)=0
We multiply parentheses ..
(+4g^2+32g+7g+56)=0
We get rid of parentheses
4g^2+32g+7g+56=0
We add all the numbers together, and all the variables
4g^2+39g+56=0
a = 4; b = 39; c = +56;
Δ = b2-4ac
Δ = 392-4·4·56
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-25}{2*4}=\frac{-64}{8} =-8 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+25}{2*4}=\frac{-14}{8} =-1+3/4 $
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