(4g-11)(g-7)=0

Solution for (4g-11)(g-7)=0 equation:

(4g-11)(g-7)=0

We multiply parentheses ..

(+4g^2-28g-11g+77)=0

We get rid of parentheses

4g^2-28g-11g+77=0

We add all the numbers together, and all the variables

4g^2-39g+77=0

a = 4; b = -39; c = +77;
Δ = b2-4ac
Δ = -392-4·4·77
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-17}{2*4}=\frac{22}{8}
=2+3/4
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+17}{2*4}=\frac{56}{8}
=7
$