(4g-6)+90=(8g)+(9g+44)

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Solution for (4g-6)+90=(8g)+(9g+44) equation: 



(4g-6)+90=(8g)+(9g+44)

We move all terms to the left:

(4g-6)+90-((8g)+(9g+44))=0

We get rid of parentheses

4g-(8g+(9g+44))-6+90=0



We calculate terms in parentheses: -(8g+(9g+44)), so:

8g+(9g+44)

We get rid of parentheses

8g+9g+44

We add all the numbers together, and all the variables

17g+44

Back to the equation:

-(17g+44)



We add all the numbers together, and all the variables

4g-(17g+44)+84=0

We get rid of parentheses

4g-17g-44+84=0

We add all the numbers together, and all the variables

-13g+40=0

We move all terms containing g to the left, all other terms to the right

-13g=-40

g=-40/-13

g=3+1/13

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