(4h+1)+(10-h)+(5h-8)=51

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Solution for (4h+1)+(10-h)+(5h-8)=51 equation: 



(4h+1)+(10-h)+(5h-8)=51

We move all terms to the left:

(4h+1)+(10-h)+(5h-8)-(51)=0

We add all the numbers together, and all the variables

(4h+1)+(-1h+10)+(5h-8)-51=0

We get rid of parentheses

4h-1h+5h+1+10-8-51=0

We add all the numbers together, and all the variables

8h-48=0

We move all terms containing h to the left, all other terms to the right

8h=48

h=48/8

h=6

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