(4j-3)-(2j+5)=0

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Solution for (4j-3)-(2j+5)=0 equation:


Simplifying
(4j + -3) + -1(2j + 5) = 0

Reorder the terms:
(-3 + 4j) + -1(2j + 5) = 0

Remove parenthesis around (-3 + 4j)
-3 + 4j + -1(2j + 5) = 0

Reorder the terms:
-3 + 4j + -1(5 + 2j) = 0
-3 + 4j + (5 * -1 + 2j * -1) = 0
-3 + 4j + (-5 + -2j) = 0

Reorder the terms:
-3 + -5 + 4j + -2j = 0

Combine like terms: -3 + -5 = -8
-8 + 4j + -2j = 0

Combine like terms: 4j + -2j = 2j
-8 + 2j = 0

Solving
-8 + 2j = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2j = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2j = 0 + 8
2j = 0 + 8

Combine like terms: 0 + 8 = 8
2j = 8

Divide each side by '2'.
j = 4

Simplifying
j = 4

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