(4k+5-4)-(2k-3k+5=)

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Solution for (4k+5-4)-(2k-3k+5=) equation: 



(4k+5-4)-(2k-3k+5=)

We move all terms to the left:

(4k+5-4)-(2k-3k+5-())=0

We add all the numbers together, and all the variables

(4k+1)-(2k-3k+5-())=0

We get rid of parentheses

4k-(2k-3k+5-())+1=0



We calculate terms in parentheses: -(2k-3k+5-()), so:

2k-3k+5-()

We add all the numbers together, and all the variables

-k

Back to the equation:

-(-k)



We add all the numbers together, and all the variables

4k-(-1k)+1=0

We get rid of parentheses

4k+1k+1=0

We add all the numbers together, and all the variables

5k+1=0

We move all terms containing k to the left, all other terms to the right

5k=-1

k=-1/5

k=-1/5

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