(4k-6/3k-9)=1/3

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Solution for (4k-6/3k-9)=1/3 equation:



(4k-6/3k-9)=1/3
We move all terms to the left:
(4k-6/3k-9)-(1/3)=0
Domain of the equation: 3k-9)!=0
k∈R
We add all the numbers together, and all the variables
(4k-6/3k-9)-(+1/3)=0
We get rid of parentheses
4k-6/3k-9-1/3=0
We calculate fractions
4k-9=0
We move all terms containing k to the left, all other terms to the right
4k=9
k=9/4
k=2+1/4

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