(4m+14)/6+7m=(7-m)/3

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Solution for (4m+14)/6+7m=(7-m)/3 equation: 



(4m+14)/6+7m=(7-m)/3

We move all terms to the left:

(4m+14)/6+7m-((7-m)/3)=0

We add all the numbers together, and all the variables

(4m+14)/6+7m-((-1m+7)/3)=0

We add all the numbers together, and all the variables

7m+(4m+14)/6-((-1m+7)/3)=0

We calculate fractions


7m+4m/()+(-((-1m+7)*6)/()=0



We calculate terms in parentheses: +(-((-1m+7)*6)/(), so:

-((-1m+7)*6)/(

We multiply all the terms by the denominator


-((-1m+7)*6)



We calculate terms in parentheses: -((-1m+7)*6), so:

(-1m+7)*6

We multiply parentheses

-6m+42

Back to the equation:

-(-6m+42)



We get rid of parentheses

6m-42

Back to the equation:

+(6m-42)



We get rid of parentheses

7m+4m/()+6m-42=0

We multiply all the terms by the denominator


7m*()+4m+6m*()-42*()=0

We add all the numbers together, and all the variables

4m+7m*()+6m*()=0

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