(4m+2)(3m-7)=0

Solution for (4m+2)(3m-7)=0 equation:

(4m+2)(3m-7)=0

We multiply parentheses ..

(+12m^2-28m+6m-14)=0

We get rid of parentheses

12m^2-28m+6m-14=0

We add all the numbers together, and all the variables

12m^2-22m-14=0

a = 12; b = -22; c = -14;
Δ = b2-4ac
Δ = -222-4·12·(-14)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-34}{2*12}=\frac{-12}{24}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+34}{2*12}=\frac{56}{24}
=2+1/3
$