(4m+8)(6m-12)=0

Solution for (4m+8)(6m-12)=0 equation:

(4m+8)(6m-12)=0

We multiply parentheses ..

(+24m^2-48m+48m-96)=0

We get rid of parentheses

24m^2-48m+48m-96=0

We add all the numbers together, and all the variables

24m^2-96=0

a = 24; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·24·(-96)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*24}=\frac{-96}{48}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*24}=\frac{96}{48}
=2
$