(4m-3)/5=(5m+2)/12

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Solution for (4m-3)/5=(5m+2)/12 equation: 



(4m-3)/5=(5m+2)/12

We move all terms to the left:

(4m-3)/5-((5m+2)/12)=0

We calculate fractions


4m/()+(-((5m+2)*5)/()=0



We calculate terms in parentheses: +(-((5m+2)*5)/(), so:

-((5m+2)*5)/(

We multiply all the terms by the denominator


-((5m+2)*5)



We calculate terms in parentheses: -((5m+2)*5), so:

(5m+2)*5

We multiply parentheses

25m+10

Back to the equation:

-(25m+10)



We get rid of parentheses

-25m-10

Back to the equation:

+(-25m-10)



We get rid of parentheses

4m/()-25m-10=0

We multiply all the terms by the denominator


4m-25m*()-10*()=0

We add all the numbers together, and all the variables

4m-25m*()=0

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