(4m-7)(m-2)=0

Solution for (4m-7)(m-2)=0 equation:

(4m-7)(m-2)=0

We multiply parentheses ..

(+4m^2-8m-7m+14)=0

We get rid of parentheses

4m^2-8m-7m+14=0

We add all the numbers together, and all the variables

4m^2-15m+14=0

a = 4; b = -15; c = +14;
Δ = b2-4ac
Δ = -152-4·4·14
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-1}{2*4}=\frac{14}{8}
=1+3/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+1}{2*4}=\frac{16}{8}
=2
$