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(4m-9)(m+3)=-18
We move all terms to the left:
(4m-9)(m+3)-(-18)=0
We add all the numbers together, and all the variables
(4m-9)(m+3)+18=0
We multiply parentheses ..
(+4m^2+12m-9m-27)+18=0
We get rid of parentheses
4m^2+12m-9m-27+18=0
We add all the numbers together, and all the variables
4m^2+3m-9=0
a = 4; b = 3; c = -9;
Δ = b2-4ac
Δ = 32-4·4·(-9)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{17}}{2*4}=\frac{-3-3\sqrt{17}}{8} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{17}}{2*4}=\frac{-3+3\sqrt{17}}{8} $
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