(4n+5)+(3n+2)+n=39

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Solution for (4n+5)+(3n+2)+n=39 equation: 



(4n+5)+(3n+2)+n=39

We move all terms to the left:

(4n+5)+(3n+2)+n-(39)=0

We add all the numbers together, and all the variables

n+(4n+5)+(3n+2)-39=0

We get rid of parentheses

n+4n+3n+5+2-39=0

We add all the numbers together, and all the variables

8n-32=0

We move all terms containing n to the left, all other terms to the right

8n=32

n=32/8

n=4

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