(4n-18)+(n+8)=(133-6n)

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Solution for (4n-18)+(n+8)=(133-6n) equation: 



(4n-18)+(n+8)=(133-6n)

We move all terms to the left:

(4n-18)+(n+8)-((133-6n))=0

We add all the numbers together, and all the variables

(4n-18)+(n+8)-((-6n+133))=0

We get rid of parentheses

4n+n-((-6n+133))-18+8=0



We calculate terms in parentheses: -((-6n+133)), so:

(-6n+133)

We get rid of parentheses

-6n+133

Back to the equation:

-(-6n+133)



We add all the numbers together, and all the variables

5n-(-6n+133)-10=0

We get rid of parentheses

5n+6n-133-10=0

We add all the numbers together, and all the variables

11n-143=0

We move all terms containing n to the left, all other terms to the right

11n=143

n=143/11

n=13

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