(4n-2)=(2n+32)

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Solution for (4n-2)=(2n+32) equation: 



(4n-2)=(2n+32)

We move all terms to the left:

(4n-2)-((2n+32))=0

We get rid of parentheses

4n-((2n+32))-2=0



We calculate terms in parentheses: -((2n+32)), so:

(2n+32)

We get rid of parentheses

2n+32

Back to the equation:

-(2n+32)



We get rid of parentheses

4n-2n-32-2=0

We add all the numbers together, and all the variables

2n-34=0

We move all terms containing n to the left, all other terms to the right

2n=34

n=34/2

n=17

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